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Re: Proof of Completeness of Algebraic Properties of Relational Lattice

From: Mikito Harakiri <mikharakiri_nospaum_at_yahoo.com>
Date: 24 May 2006 10:00:25 -0700
Message-ID: <1148490025.153620.203650@i40g2000cwc.googlegroups.com>


Vadim Tropashko wrote:
> Existence of distributor hinges on the following
> inequality:
>
>
> A /\ (B \/ C) >= (A /\ B) \/ (A /\ C)

This identity is true in any lattice, not only relational one. Hence it can be proved witut need to invoke distributivity criteria.

  1. A /\ (B \/ C) >= (A /\ B)

Proof: A /\ (B \/ C) /\ (A /\ B) = A /\ B /\ (B \/ C) = A /\ B

2. A /\ (B \/ C) >= (A /\ C)

3. A /\ (B \/ C) >= (A /\ B) \/ (A /\ C) Received on Wed May 24 2006 - 12:00:25 CDT

Original text of this message

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