# Re: Box query

Date: 23 Apr 2006 12:55:42 -0700

Message-ID: <1145822142.149564.77670_at_g10g2000cwb.googlegroups.com>

Try a slightly different approach. Begin with one dimension and stronger DDL:

INSERT INTO Boxes VALUES ('A', 'x', 0, 2); INSERT INTO Boxes VALUES ('B', 'x', 1, 3); INSERT INTO Boxes VALUES ('C', 'x', 10, 12);

--in 1 dimension

SELECT B1.box_id, B2.box_id

FROM Boxes AS B1, Boxes AS B2

WHERE B1.box_id < B2.box_id

AND (B1.high - B1.low) + (B2.high - B2.low)

> ABS(B1.high - B2.low);

This says that two lines segements overlap when their combined lengths are less than their span in the dimension. Math rather than between-ness.

/* the cubes A={(x,0,2),(y,0,2),(z,0,2)} and B={(x,1,3),(y,1,3),(z,1,3)} intersect, while the box C={(x,10,12),(y,0,4),(z,0,100)} */

let's go to 2D

INSERT INTO Boxes VALUES ('A', 'y', 0, 2); INSERT INTO Boxes VALUES ('B', 'y', 1, 3); INSERT INTO Boxes VALUES ('C', 'y', 0, 4);

--in 2 dimension: first shot:

SELECT B1.box_id, B2.box_id, B1.dim

FROM Boxes AS B1, Boxes AS B2

WHERE B1.box_id < B2.box_id

AND B1.dim = B2.dim

AND (B1.high - B1.low) + (B2.high - B2.low)

> ABS(B1.high - B2.low);

Now look for a common area in (x,y) by having overlaps in both dimensions:

SELECT B1.box_id, B2.box_id

FROM Boxes AS B1, Boxes AS B2

WHERE B1.box_id < B2.box_id

AND B1.dim = B2.dim

AND (B1.high - B1.low) + (B2.high - B2.low)

> ABS(B1.high - B2.low)

GROUP BY B1.box_id, B2.box_id

HAVING COUNT(B1.dim) = 2;

--3 dimensions:

INSERT INTO Boxes VALUES ('A', 'z', 0, 2); INSERT INTO Boxes VALUES ('B', 'z', 1, 3); INSERT INTO Boxes VALUES ('C', 'z', 0, 100);

Now change the HAVING clause to COUNT(B1.dim) = 3 or (SELECT COUNT (DISTINCT dim) FROM Boxes) if you do not know the space you are using. Received on Sun Apr 23 2006 - 21:55:42 CEST