Re: circular relationships ok?

Brian Selzer wrote:
> If I follow your notation,
>
> forall b (b in Br --> b in Bs) is true and
> forall b (b in Bs --> b in Br) is also true, and must be because of the
> circular foreign key relationship.

Right, I forgot about the relationship being circular. In this case, you are aboslutely right -- all the sets will be of the same size.

[...]
> >
Received on Sat Mar 04 2006 - 22:01:01 CST