Re: General Graphs in SQL

From: <amado.alves_at_netcabo.pt>
Date: 16 Dec 2005 03:47:14 -0800
Message-ID: <1134733634.629871.173710_at_g44g2000cwa.googlegroups.com>


> A
> / \
> B C
> | \ |
> F D
> |
> E
>
> Each path is assigned an id number and the steps are numbered from zero
> (the start of the path) to (k), the final step. Using the simple six
> node graph, the one edge paths are:
>
> 1 0 A
> 1 1 B
> 2 0 B
> 2 1 F
> 3 0 C
> 3 1 D
> 4 0 B
> 4 1 D
> 5 0 D
> 5 1 E

Is this incomplete on purpose? (Path AC, and the inverse paths BA, CA... are missing.) Received on Fri Dec 16 2005 - 12:47:14 CET

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