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Home -> Community -> Usenet -> comp.databases.theory -> Re: Distributivity in Tropashko's Lattice Algebra
Mikito Harakiri wrote:
> VC wrote:
> > "Mikito Harakiri" <mikharakiri_nospaum_at_yahoo.com> wrote in message
> > news:1124225375.601615.162210_at_g47g2000cwa.googlegroups.com...
> > >
> > > vc wrote:
> > >> A union '00' = '00'.
Sorry, I meant A union '00' = '01', of course. Was confused by your unorthodox union.
> There is another argument against
>
> A union 00 = 00
>
> For any two relations A and B, the relation
>
> A union B
>
> has cardinality bigger than both A and B. In you proposition this
> property is lost.
Right. See above.
To sum up, the three '1' '0' combinations are :
00 union A = 01
00 join A = 'a0' where 'a' is A's set of attrs.
01 union A = 01
01 join A = A
10 union A = A
10 join A = 10
Received on Wed Aug 17 2005 - 13:44:20 CDT
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