Re: Questions about nested intervals. Help me please!!!

From: Mikito Harakiri <mikharakiri_nospaum_at_yahoo.com>
Date: 19 Jul 2005 16:12:12 -0700
Message-ID: <1121814732.301276.128200_at_g14g2000cwa.googlegroups.com>


Vadim Tropashko wrote:
> Remember, we (rather arbitrarily) selected node [[30,37],[73,90]] as a
> ... there is a matrix that satisfies the equation
>
> [[2,7],[5,17]]*[[a,b],[c,d]]=[[30,37],[73,90]]
>
> Here I take a little jump, assuming that finding a,b,c,d is easy for
> anybody with rudimentary linear algebra skills.

This is fairly easy. What is the inverse of [[2,7],[5,17]]? For 2x2 matrices the inverse calculation is trivial:

[[x11,x12],[x21,x22]]^(-1) =
det([[x11,x12],[x21,x22]]) * [[x22,-x12],[-x21,x11]]

which gives in this case

[[2,7],[5,17]]^(-1) = [[-17,7],[5,-2]]

Left mutiply

[[2,7],[5,17]]*[[a,b],[c,d]]=[[30,37],[73,90]]

both sides by [[-17,7],[5,-2]]

[[a,b],[c,d]]=[[-17,7],[5,-2]]*[[30,37],[73,90]]=[[1,1],[4,5]] Received on Wed Jul 20 2005 - 01:12:12 CEST

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