Re: Transitive Closure

Paul <paul_at_test.com> wrote in message news:<Hu2qc.4347$wI4.496108_at_wards.force9.net>...  

> What we're talking about here which I think is what Alfredo is
> misunderstanding is commutativity of the "composition of operators"
> operator.

What do you call composition?

To an n-ary operator?

> So say we have unary operators f and g we can define the
> operator "f*g" to be:
>
> (f*g)(x) = f(g(x)) for all x.
>
> Commutativity of this "*" operation just means that:

So "*" is a binary operation.

Regards
  Alfredo Received on Tue May 18 2004 - 12:33:10 CEST