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>>Do you have an example problem requiring recursion for which
transitive closure provides no solution? <<
The Ackermann function, for one:
A(0, m) = m+1 A(n+1, 0) = A(n, 1) A(n+1, m+1) = A(n, A(n+1, m))Received on Fri Mar 14 2003 - 18:35:10 CST