Re: Relation problem

From: Jan Hidders <hidders_at_REMOVE.THIS.win.tue.nl>
Date: 30 Jan 2001 10:19:55 GMT
Message-ID: <9564gb$eqj$3@news.tue.nl>

Michel wrote:
> This sounds like you are putting the partyID into the person table OR the
> org table. So a person needs a party or an Org needs a party. So if a
> person has 2 addresses then you have to create the person twice with a
> different partyID.

The relationship between Party and Address is implemented by a separate table and can therefore be a many-to-many relationship.

-- 
  Jan Hidders

Received on Tue Jan 30 2001 - 04:19:55 CST