Re: Duplicate Records
From: Ewan Scott <ewan.scott_at_ed.ac.uk>
Date: 1996/10/29
Message-ID: <3276497E.7E55_at_ed.ac.uk>#1/1
Date: 1996/10/29
Message-ID: <3276497E.7E55_at_ed.ac.uk>#1/1
While working on a similar problem I used the following;
select a, b, c
from table
having count(*) > 1
group by a, b, c
This worked for me, hope it helps you out.
Ewan Scott. Received on Tue Oct 29 1996 - 00:00:00 CET