Re: Subtracting dates, any help is welcome
From: Andrew Hodgson <andrew_at_tcamiga.demon.co.uk>
Date: Mon, 27 Jul 1998 23:14:27 +0100
Message-ID: <ZuIokAADvPv1EwFx_at_tcamiga.demon.co.uk>
Date: Mon, 27 Jul 1998 23:14:27 +0100
Message-ID: <ZuIokAADvPv1EwFx_at_tcamiga.demon.co.uk>
In article <35AC7A59.6BA5DE2C_at_nl.uu.net>, "J. van der Laan"
<jan_at_nl.uu.net> writes
>Hello,
>
>Surely this is pretty simple....but how simple it is I do not know.
>
>I want to subtract two dates from eachother and want the output to be in
>hours/minutes/seconds.
>
>The only thing I did achieve until now is;
>SQL statement;
># select sum(out_time-in_time) from database where field=value;
>
>Output;
>SUM(OUT_TIME-IN_TIME)
>---------------------
> .053784722
>
>What does this output value say/mean???
>btw; The OUT_TIME and IN_TIME fields are of type DATE.
>
>Thanks in advance,
>
> Jan.
>
>
Try
select to_char(sum(out_time-in_time),'HH:MI') from database where field=value;
| Andrew Hodgson - Andrew_at_tcamiga.demon.co.uk | | www.tcamiga.demon.co.uk | | Amiga 1200 030 33Mhz | 6x86 P150+ | | 250Mb HD HD Disk Drive | Quad Spd CD 5.3 Gb HD | | 6Mb Ram | CDTV | Motorola SurfR 56K | 80Mb Ram | Resistance is futile...Received on Tue Jul 28 1998 - 00:14:27 CEST