Re: Oracle 10g Question

On Jan 24, 11:59 am, Maxim Demenko <mdeme..._at_gmail.com> wrote:
> ame..._at_iwc.net schrieb:
>
>
>
> > Hi All,
>
> > I'm playing with Oracle 10g Regular Expressions. I have a string that
> > looks like this, basically a comma delimited string:
>
> > z VARCHAR2(40) := '1:3,4:6,8:10,3:4,7:6,11:12';
>
> > What I want to do is basically parse this string. This this example,
> > the 1 would go into the first variable, then the 3 into the second
> > variable, and same for the rest of the string.
>
> > I know Oracle has some comma_to_table routine, but I want to try this
> > using these regular expressions. I was using something like this
> > with no luck:
>
> > x := REGEXP_SUBSTR(z,'[^:]+', 1, 1);
>
> > This returns 1 for the result, which is correct for the first item,
> > but that is as far as I can get.
>
> > So, I want to parse this string using a comma as the delimiter between
> > pairs, and then a colon within that to get the 2 values for the
> > variables.
>
> > Can this be done using the REGEXP_SUBSTR function???
>
> > Thanks!
>
> Maybe not exactly what you expect, but you can try to play around...
>
> SQL> with t as (
> 2 select '1:3,4:6,8:10,3:4,7:6,11:12' z from dual
> 3 )
> 4 select
> 5 rtrim(regexp_substr(z,'\d+:',1,level),':') first,
> 6 ltrim(regexp_substr(z,':\d+',1,level),':') second
> 7 from t
> 8 connect by level<=length(z)-length(replace(z,',')) + 1
> 9 /
>
> FIRST SECOND
> ----- ------
> 1 3
> 4 6
> 8 10
> 3 4
> 7 6
> 11 12
>
> 6 rows selected.
>
> Best regards
>
> Maxim

Yours is interesting. I'll have to do some reading. I have never seen the 'with' command, and, I really do not know what 'connect by' does.

Also, I'll have to implement this into a PL/SQL routine and for each pair, insert them into a table.....

More investigation....... Received on Thu Jan 24 2008 - 12:10:44 CST