Oracle FAQ | Your Portal to the Oracle Knowledge Grid |
Home -> Community -> Usenet -> c.d.o.server -> Re: Can this be done in SQL? Find the transitive relation
On 4 Aug., 21:06, "da. Ram" <dba2..._at_yahoo.com> wrote:
> Dear Group,
>
> I am strugling get the following done in SQL. Could anyone help me to
> figure out a way?
>
> Oracle version 8i .
>
> create table t_grp (id1 char(1), id2 char(2)) ;
>
> insert into t_grp values ('A','C'); --> A:C are related
> insert into t_grp values ('B','D'); --> B:D are related
> insert into t_grp values ('F','H');
> insert into t_grp values ('G','H');
> insert into t_grp values ('B','G');
> insert into t_grp values ('X','Y');
> insert into t_grp values ('W','Y');
>
> I want to group the values based on the following rules,
>
> 1, if any of the value from id1 or id2 can be linked to any other
> values,
> they all will be treated as one group
>
> Ex, in the above case
> A has relationship to C, neither of them has any other relationship to
> any
> other values in the table
> B has relationship to D, B has relationship to G, G has relationship
> to H, H
> has relationship to F
> F has relationship to H, H has relationship to G ...
>
> A:C - Group 1 (A,C) - new elements
> B:D -> B:G -> G:H -> H:F - Group 2 (B, D, G, H, F)
> F:H -> H:G -> G:B -> B:D - Group 2 (F, H, G, B, D) - same elements as
> above
> G:H -> G:B -> H:F -> B:D - Group 2 (G, H, B, F, D) - do -
> G:B -> G:H -> H:F -> B:D - Group 2 (G, B, H, F, D) - do -
> X:Y -> Y:W - Group 3 (X, Y, W) - new set of elements
>
> My objective is to get the final result in the below form.
>
> grp id1 id2
> ----- ------ ------
> 1 A C
> 2 B D
> 2 F H
> 2 G H
> 2 B G
> 3 X Y
> 3 W Y
>
> The following output is also fine [This would be the final output, but
> I can covert from the above to this one]
>
> grp id
> ---- -------
> 1 A
> 1 C
> 2 B
> 2 D
> 2 F
> 2 H
> 2 G
> ...
> 3 X
> 3 Y
> 3 W
> 3 Y
>
> Thank you.
Hi,
I don't know how to do this in SQL, but maybe you can evade to pl/sql. Either by precomputing groups or by using pipeline functions (but I guess 8i does not know about pipline functions yet ...)
regards,
stephan
Received on Mon Aug 06 2007 - 06:38:47 CDT