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Home -> Community -> Usenet -> c.d.o.server -> Re: dbms_jobs once an hour at the bottom of the hour

Re: dbms_jobs once an hour at the bottom of the hour

From: Michel Cadot <micadot{at}altern{dot}org>
Date: Tue, 22 Nov 2005 18:52:06 +0100
Message-ID: <43835ac5$0$4331$626a54ce@news.free.fr>

"Syltrem" <syltremzulu_at_videotron.ca> a écrit dans le message de news: 11o69aean6e1p06_at_corp.supernews.com...
|
| "Michel Cadot" <micadot{at}altern{dot}org> wrote in message
| news:4382157f$0$4360$626a54ce_at_news.free.fr...
| > | >
| > | > dbms_job.submit (..., next_date=>trunc(sysdate,'HH')+3/24/2,
| > | > interval=>'trunc(sysdate,''HH'')+3/24/2',...);
| > | >
| > | > Regards
| > | > Michel Cadot
| > | >
| > | >
| > |
| > | How did you come up with this?
| > | I see the trunc(sysdate,'HH') comes up with the current hour but the
| > 3/24/2
| > | is a mystery to me.
| > |
| > |
| >
| > Well, 1 is a day, 1/24 is one hour, 3/24/2 is 1.5 hour.
| > So truncating to the hour and adding 1.5 hour give me
| > 30 minutes after the next hour.
| >
|
| Bonjour Michel
|
| Would you also have a clever way of getting the time that would represent
| the next half hour?
| I can't find a way...
| 1:00, then 1:30, then 2:00, 2:30, etc for running a job every 30 minutes.
|
| Thanks
| Syltrem
|

trunc(sysdate,'HH')+decode(sign(to_number(to_char(sysdate,'MI'))-30),1,2,1)/48

Regards
Michel Cadot Received on Tue Nov 22 2005 - 11:52:06 CST

Original text of this message

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