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Home -> Community -> Usenet -> c.d.o.server -> Re: storage problem
One possibility:
The table has PCTFREE = 10.
Your rows have grown to take up ALL the free space
You recreate the table with PCTFREE = 10
therefore you need ca. 10% more blocks
-- Regards Jonathan Lewis http://www.jlcomp.demon.co.uk The educated person is not the person who can answer the questions, but the person who can question the answers -- T. Schick Jr One-day tutorials: http://www.jlcomp.demon.co.uk/tutorial.html ____UK_______April 22nd ____Denmark__May 21-23rd ____USA_(FL)_May 2nd Three-day seminar: see http://www.jlcomp.demon.co.uk/seminar.html ____UK_(Manchester)_May ____Estonia___June (provisional) ____Australia_June (provisional) ____USA_(CA, TX)_August The Co-operative Oracle Users' FAQ http://www.jlcomp.demon.co.uk/faq/ind_faq.html "Yun Guan" <yguan_at_houston.rr.com> wrote in message news:KaMka.46909$rd4.1480568_at_twister.austin.rr.com...Received on Tue Apr 08 2003 - 23:52:00 CDT
> I have one table anaylyzed using "compute statistics". It has 2774
Blocks,
> which spans over 3 extents, chain_cnt=0, block_size 8192,
ave_row_len=47. I
> decided to move all data into one larger extent. So I dropped the
table,
> recreate the table with initial extent = 22M (> 2774 x 8/1024) with
all
> other storage parameters unchanged. After re-analyzing it, the table
has
> 3015 blocks and spans over 2 extents. I could not figure out why the
block
> number increases with chain_cnt =0. It spans over 2 extents, not 1
extent
> as I expected.
>
> Can anybody advise? Thanks in advance.
>
>
> --
> Allen Guan
> yguan_at_houston.rr.com
>
>