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Re: confusing date question

From: Lothar Armbruester <lothar.armbruester_at_t-online.de>
Date: Mon, 22 Jul 2002 18:22:45 +0200
Message-ID: <PM0003A65FB7C9AD85@hades.none.local>


Cynic wrote:
> I have a script that updates dates on a db. However, now I am supposed
> to
> take into account the day of the week. So, for example, if the date is
> July
> 7, 1999 (Wednesday) I need to update to July 7, 2001. HOWEVER: if July
> 7,
> 2001 is NOT a thursday, but a SATURDAY, I need to make it a
> non-weekend work
> day. So here is what I need to do:
>
> July 7, 1999 ---->>> July 9, 2001 (this is the first work day
> following
> July 7, 2001)
> So, I guess I am adding 2 years here PLUS whatever it will take to get
> the
> day to the work week.
> Any suggestions?
>
> Here is what I have so far (doesn't take into consideration the whole
> weekend thing):
>
> UPDATE GL_ACCT_SCHED SET EFF_DT = ADD_MONTHS(EFF_DT,
> (TRUNC((MONTHS_BETWEEN( TO_DATE('31-DEC-2000', 'DD-MON-YYYY'),
> EFF_DT))/12,0)*12)+12) where MONTHS_BETWEEN(TO_DATE('01-JAN-2001',
> 'DD-MON-YYYY'), EFF_DT) > 0;
>

Hello Cynic, try this:

update gl_acct_sched set

   eff_dt = add_months(eff_dt,24)+

            decode(to_char(add_months(eff_dt,24),'D'),'6',2,'7',1,0) where

   eff_dt<to_date('2001-01-01','YYYY-MM-DD');

If I understood your problem correctly, you want to add two years to your dates plus a small offset bringing them to the next workday. add_months(eff_dt,24) adds the two years. to_char(add_months(eff_dt,24),'D') gives the day of week '1' being monday. So the decode adds two days for saturday, one day for sunday and nothing for all other days.

Hope that helps,
Lothar

-- 
Lothar Armbrüster       | la_at_oktagramm.de
Hauptstr. 26            | la_at_heptagramm.de
D-65346 Eltville        | lothar.armbruester_at_t-online.de
Received on Mon Jul 22 2002 - 11:22:45 CDT

Original text of this message

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