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a correction...
"Mr Taki" <nospam_at_localhost.spamwarn> wrote in message
news:S9p56.76$K12.490_at_nntpserver.swip.net...
>
(snip)
> I mean, generally Raid 5 has n+1 disks for a striped array with the
> parity evenly distributed. **For every write there are data stripes
> writes and a parity caclulation and a write of parity to one of the
> disks (done in parallell?).** So, even if the whole array width in
Messed up there. Still, all else applies (I hope!)... It should say something like:
For every write there are data stripes read, a parity calculation, and a write of data and parity. (So a write needs a "extra" read access and parity calculation).
Cheers!
/Fad
(more snipped, see previous post) Received on Fri Jan 05 2001 - 15:15:16 CST