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Re: SQL

From: Brian Vuong <brian-vuong_at_usa.net>
Date: 2000/06/26
Message-ID: <slf7mj5qjev86@corp.supernews.com>#1/1

Both instructions from Haken and Del worked. I really appreciate your helps.

Brian Vuong

Del Jenkins wrote in message ...
>Hi
>If I have understod you properly I believe the following Select statement
>will return the results you are looking for;
>
> SELECT ACCTNO, SSN
> FROM table1
> WHERE exists
> (select SSN
> FROM table1
> GROUP BY SSN
> HAVING COUNT(SSN)>1)
> ORDER BY SSN;
>
>Let me know if this does the trick. Good luck.
>
>Del
>
>"Brian Vuong" <brian-vuong_at_usa.net> wrote in message
>news:sl80dq8je7f124_at_corp.supernews.com...
>>
>> Could someone help me with this. I have two fields, acctno ( account
>> number) and ssn. I would like to write a query to obtain only the
 customers
>> that have more than one account. To determine if someone has more than
 one
>> account by checking for duplicate ssn. Both ssn and acctno are character
>> fields. I spent two days to try to figure out, but I could not do it.
>> There is only 1 table
>>
>>
>>
>> select acctno, name, ssn
>> from table1
>> where count(ssn)>1; <----------------this does not work.
>>
>>
>> Sincerely,
>>
>> Brian
>>
>>
>
>
Received on Mon Jun 26 2000 - 00:00:00 CDT

Original text of this message

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