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Re: SQL question

From: fumi <fumi_at_tpts5.seed.net.tw>
Date: 15 Oct 1999 17:50:46 GMT
Message-ID: <7u7phm$gcv$5@news.seed.net.tw>

Rexx <nebacar_nospam_at_eunet.yu> wrote in message news:7u4cjm$t58$1_at_SOLAIR2.EUnet.yu...
> HI,
>
> can I do in SQL next query
>
> I have table (eg.) T1 with two columns SMM and DATUM
>
> SMM DATUM
> --------- -----------
> 1000 1-10-1997
> 1000 1-10-1998
> 1000 1-10-1999
>
> 2000 1-10-1997
> 2000 1-10-1998
>
> 3000 1-10-1997
> 3000 1-10-1998
> 3000 1-10-1999
>
> 4000 1-10-1997
> 4000 1-10-1998
>
> I need to get "mising " records
>
> 2000 1-10-1999
> 4000 1-10-1999

If you means that the records in your table should form a "matrix", here is the solution:

SQL> create table t1(smm number, datum varchar2(20));

Table created.

SQL> insert into t1 values (1000, '1-10-1997');

1 row created.

SQL> insert into t1 values (1000, '1-10-1998');

1 row created.

SQL> insert into t1 values (1000, '1-10-1999');

1 row created.

SQL> insert into t1 values (2000, '1-10-1997');

1 row created.

SQL> insert into t1 values (2000, '1-10-1998');

1 row created.

SQL> insert into t1 values (3000, '1-10-1997');

1 row created.

SQL> insert into t1 values (3000, '1-10-1998');

1 row created.

SQL> insert into t1 values (3000, '1-10-1999');

1 row created.

SQL> insert into t1 values (4000, '1-10-1997');

1 row created.

SQL> insert into t1 values (4000, '1-10-1998');

1 row created.

SQL>
SQL> select m.*
  2 from (select * from (select distinct smm from t1),   3 (select distinct datum from t1)) m, t1   4 where m.smm=t1.smm(+) and t1.smm is null   5 and m.datum=t1.datum(+) and t1.datum is null;

      SMM DATUM

--------- --------------------
     2000 1-10-1999
     4000 1-10-1999




Received on Fri Oct 15 1999 - 12:50:46 CDT

Original text of this message

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