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A copy of this was sent to Nandakumar <nanban_at_my-deja.com>
(if that email address didn't require changing)
On Thu, 29 Jul 1999 18:52:17 GMT, you wrote:
> Anyone has an idea as to where this PROCEDURE
> RAISE_APPLICATION_ERROR (number,'mesg') would print the message.
> The serveroutpt flag is set.
>
> When this procedure is invoked from within a function, it does not
> print the message anywhere.
>
> When invoked from SQL prompt this is what happens!
> SQL> execute raise_application_error(-20001,'hi')
> begin raise_application_error(-20001,'hi'); end;
>
> *
> ERROR at line 1:
> ORA-20001: hi
> ORA-06512: at line 1
>
> Anything wrong with the above code?
>
> Thanks
lets see the code for your function. I'll bet it has an exception handler with a WHEN OTHERS clause and hence the raised error is being caught and ignored.
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Opinions are mine and do not necessarily reflect those of Oracle Corporation Received on Thu Jul 29 1999 - 14:18:34 CDT