Taking floor of date

I've got a table with a DATE datatype column in it. I want to select all the rows which contain dates which are the same calendar day as another date I've got. What's the best way to do that?

One way I can see to do that would be to take the integer part of my selection date, which would give me time 00:00:00 of that date, then add 1 to it, giving me 00:00:00 of the next date, then doing:

select * from table where date >= midnight_today and date < midnight_tomorrow

but I don't see any way to do the "take the integer part" bit.

The only way I can see to do this is to use the to_char function, converting just the year, month, and day-of-month, then use to_date to convert that back to a DATE datatype, but that's pretty gross.

--
Roy Smith <roy_at_popmail.med.nyu.edu>
New York University School of Medicine Received on Thu May 13 1999 - 08:57:09 CDT