Re: HELP !!! SQL GURUS !!!! How do I do this ???

If your 'known' values are in a table as well, you can try using MINUS, as in this example:

select colName from known_values_table
MINUS
select colName from other_table

This will give you the values in known_values_table that are not in other_table.

Jens U. Veigel wrote:
>
> Hey Pro's
>
> Got a problem.
>
> I'm trying to slelect a column which has numbers in it lets say 1
> through 5, and compare it to a list of known values.
> Lets say 1 through10.
> I would like it to come back with all the matching numbers that are
> not in the column such as 6,7,8,9,10.
>
> I was trying somthing like this:
>
> select column
> from table
> where column is not in
>
> (select column from
> table
> where column is in ('1','2','3','4','5','6','7','8','9',10')
>
> then it returns 1,2,3,4,5
>
> what I need it to return is 6.7,8,9,10
> (the exact opposite)
>
> It seems so simple, what am I doing wrong ??
> Thanks for reading it !
>
> Jens
>
> jens_at_deutschware.com
>
 

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