Re: Linking records together

From: ddf <oratune_at_msn.com>
Date: Wed, 23 Sep 2009 11:58:59 -0700 (PDT)
Message-ID: <c74b067b-b52a-4c54-8455-619d3f595355_at_m11g2000vbl.googlegroups.com>



On Sep 23, 12:36 pm, "PJ" <pjv_dev.nos..._at_geenspam.hotmail.com> wrote:
> I should have known, the sample data is too easy. It won't work with more
> than two records per item. Real world will have a varying number of records
> per item, probably with an average of 6.
>
> PJ
>
> "ddf" <orat..._at_msn.com> wrote in message
>
> news:7c8b9226-0a29-47ef-9340-0f40c1c9ca64_at_g6g2000vbr.googlegroups.com...
> On Sep 23, 8:22 am, "PJ" <pjv_dev.nos..._at_geenspam.hotmail.com> wrote:
>
>
>
>
>
> > Hi all,
>
> > We need to track work items across several existing applications. Items
> > can
> > start as a document on disk, can be renamed or moved, converted to a task
> > in an application, until they reach a certain state. The applications know
> > nothing about preceding or following applications and there is no common
> > identifier for the items, which has always been a good thing.
>
> > My idea is to create a table for all events. Each application will record
> > their
> > own events. A minimum is one event per application with a starting and
> > finishing situation for that application. Example: "file \\folder1\x.doc
> > was
> > moved to \\folder2\y.doc". Another application may follow up with
> > "\\folder2\y.doc was archived with id 12345". Each event will have a date
> > and time.
>
> > My table will probably have the following columns:
>
> > event_id number(10)
> > start_item varchar2(255)
> > end_item varchar2(255)
> > event_date date
>
> > Sample data:
>
> > 1 A B 2009-10-11
> > 2 G H 2009-10-12
> > 3 B C 2009-10-13
> > 4 H I 2009-10-17
>
> > Records can be linked from end_item to start_item (the next application in
> > line will continue where the previous application stops). So in this
> > sample
> > data I have two sets of records (1 with 3, 2 with 4) and recognize two
> > starting points A and G with two end points C and I. From A to C takes
> > two days, from G to I takes 5 days.
>
> > Data entry is no problem. Reporting is. My resultset (a view, another
> > table)
> > should be this:
>
> > A C 2
> > G I 5
>
> > How can I achieve this? I have looked at the connect by, but I get to many
> > records. So basically I have no idea where to start.
>
> > Thanks in advance,
> > PJ
>
> You're making this too difficult:
>
> SQL> create table event_track(
>   2          event_id number(10),
>   3          start_item varchar2(255),
>   4          end_item varchar2(255),
>   5          event_date date
>   6  );
>
> Table created.
>
> SQL>
> SQL>
> SQL> insert all
>   2  into event_track
>   3  values(1,'A','B',to_date('2009-10-11', 'RRRR-MM-DD'))
>   4  into event_track
>   5  values(2,'G','H',to_date('2009-10-12', 'RRRR-MM-DD'))
>   6  into event_track
>   7  values(3,'B','C',to_date('2009-10-13', 'RRRR-MM-DD'))
>   8  into event_track
>   9  values(4,'H','I',to_date('2009-10-17', 'RRRR-MM-DD'))
>  10  select * from dual;
>
> 4 rows created.
>
> SQL>
> SQL> commit;
>
> Commit complete.
>
> SQL>
> SQL> column start_item format a10
> SQL> column end_item format a10
> SQL>
> SQL> select e1.event_id, e1.start_item, e2.end_item, round
> (e2.event_date - e1.event_date, 0) event_days
>   2  from event_track e1, event_track e2
>   3  where e2.start_item = e1.end_item;
>
>   EVENT_ID START_ITEM END_ITEM   EVENT_DAYS
> ---------- ---------- ---------- ----------
>          1 A          C                   2
>          2 G          I                   5
>
> SQL>
>
> David Fitzjarrell- Hide quoted text -
>
> - Show quoted text -

I gave this a try and it appears to be working:

SQL> --
SQL> -- Create table
SQL> --
SQL> create table event_track(
  2          event_id number(10),
  3          start_item varchar2(255),
  4          end_item varchar2(255),
  5          event_date date

  6 );

Table created.

SQL>
SQL> --
SQL> -- Load data
SQL> --
SQL> insert all

  2 into event_track
  3 values(1,'A','B',to_date('2009-10-11', 'RRRR-MM-DD'))   4 into event_track
  5 values(2,'G','H',to_date('2009-10-12', 'RRRR-MM-DD'))   6 into event_track
  7 values(3,'B','C',to_date('2009-10-13', 'RRRR-MM-DD'))   8 into event_track
  9 values(4,'H','I',to_date('2009-10-17', 'RRRR-MM-DD'))  10 into event_track
 11 values(5,'C','D',to_date('2009-10-19', 'RRRR-MM-DD'))  12 into event_track
 13 values(6,'I','J',to_date('2009-10-22', 'RRRR-MM-DD'))  14 into event_track
 15 values(7,'J','K',to_date('2009-10-23', 'RRRR-MM-DD'))  16 into event_track
 17 values(8,'D','E',to_date('2009-10-27', 'RRRR-MM-DD'))  18 select * from dual;

8 rows created.

SQL>
SQL> commit;

Commit complete.

SQL>
SQL> column start_item format a10
SQL> column end_item format a10
SQL>
SQL> --
SQL> -- Display source data
SQL> --
SQL> select event_id, start_item, end_item ,event_date
  2 from event_track;

  EVENT_ID START_ITEM END_ITEM EVENT_DATE

---------- ---------- ---------- --------------------
         1 A          B          11-OCT-2009 00:00:00
         2 G          H          12-OCT-2009 00:00:00
         3 B          C          13-OCT-2009 00:00:00
         4 H          I          17-OCT-2009 00:00:00
         5 C          D          19-OCT-2009 00:00:00
         6 I          J          22-OCT-2009 00:00:00
         7 J          K          23-OCT-2009 00:00:00
         8 D          E          27-OCT-2009 00:00:00

8 rows selected.

SQL>
SQL> --
SQL> -- Generate desired report
SQL> --
SQL> with etrack as(
  2          select e1.event_id, e1.start_item, e2.end_item,
e2.event_date edate2, e1.event_date edate1
  3          from event_track e1, event_track e2
  4          where e2.start_item = e1.end_item
  5 )
  6 select e11.event_id, e11.start_item, e21.end_item, round (e21.edate2 - e11.edate1,0) evt_days
  7 from etrack e11, etrack e21
  8 where e21.start_item = e11.end_item   9 order by 1;

  EVENT_ID START_ITEM END_ITEM EVT_DAYS ---------- ---------- ---------- ----------

         1 A          E                  16
         2 G          K                  11

SQL> Test it on your data to see if the query returns correct results.

David Fitzjarrell Received on Wed Sep 23 2009 - 13:58:59 CDT

Original text of this message