"Maxim Demenko" <mdemenko_at_gmail.com> wrote in message
news:4749AD5E.1070804_at_gmail.com...
> Jeff B schrieb:
>>
>> "Maxim Demenko" <mdemenko_at_gmail.com> wrote in message
>> news:47499F3F.1080209_at_gmail.com...
>>> Jeff B schrieb:
>>>> "Charles Hooper" <hooperc2000_at_yahoo.com> wrote in message
>>>> news:4ed69188-f428-46dd-86f0-8850efb9faa9_at_n20g2000hsh.googlegroups.com...
>>>>> On Nov 25, 9:52 am, "Jeff B" <jef..._at_KnoSpam.tds.net> wrote:
>>>>>> Hi everyone,
>>>>>>
>>>>>> I have a book table and in that table it has the book tile,
>>>>>> publisher, and
>>>>>> type of book it is. example mystery, scifi, etc...
>>>>>>
>>>>>> I am trying to write a query that brings back a list of every pair of
>>>>>> books
>>>>>> that have the same publisher and same book type. I have been able to
>>>>>> get
>>>>>> the following code to work:
>>>>>>
>>>>>> select publisher_code, type
>>>>>> from book
>>>>>> group by publisher_code, type
>>>>>> having count(*) > 1;
>>>>>>
>>>>>> which returns the following results:
>>>>>>
>>>>>> PU TYP
>>>>>> -- ---
>>>>>> JP MYS
>>>>>> LB FIC
>>>>>> PE FIC
>>>>>> PL FIC
>>>>>> ST SFI
>>>>>> VB FIC
>>>>>>
>>>>>> I can not figure out how to get the book title and book code for the
>>>>>> books
>>>>>> that this result list represents, everything i have tried throws out
>>>>>> an
>>>>>> error.
>>>>>>
>>>>>> Can someone help?
>>>>>>
>>>>>> Thanks,
>>>>>>
>>>>>> Jeff
>>>>>
>>>>> I see two possible methods:
>>>>> 1. Slide the SQL statement that you have written into an inline view,
>>>>> join the inline view to your book table, and then use the
>>>>> publisher_code, type columns to drive back into your book table. The
>>>>> join syntax may look like one of the following: (publisher_code, type)
>>>>> IN (SELECT...) or b.publisher_code=ib.publisher_code and
>>>>> b.type=ib.type
>>>>> 2. Use analytical functions (COUNT() OVER...) to determine the number
>>>>> of matches for the same publisher_code, type columns. Then slide this
>>>>> SQL statement into an inline view to retrieve only those records with
>>>>> the aliased COUNT() OVER greater than 1. This has the benefit of
>>>>> retrieving the matching rows in a single pass.
>>>>>
>>>>> You will likely find examples of the above approaches in this and the
>>>>> comp.databases.oracle.server group.
>>>>>
>>>>> Charles Hooper
>>>>> IT Manager/Oracle DBA
>>>>> K&M Machine-Fabricating, Inc.
>>>>
>>>> Hi Charles,
>>>>
>>>> Thanks for the response. I can not say that I understand everything
>>>> that you were saying. When you say inline view do you mean like this?
>>>>
>>>> select title
>>>> from book
>>>> where publisher_code and type in
>>>> (select publisher_code, type
>>>> from book
>>>> group by publisher_code, type
>>>> having count(*) > 1);
>>>>
>>>> this did not work it threw back the following error:
>>>>
>>>> SQL> select title
>>>> 2 from book
>>>> 3 where type in
>>>> 4 (select publisher_code, type
>>>> 5 from book
>>>> 6 group by publisher_code, type
>>>> 7 having count(*) > 1);
>>>> (select publisher_code, type
>>>> *
>>>> ERROR at line 4:
>>>> ORA-00913: too many values
>>>>
>>>>
>>>> SQL> select title
>>>> 2 from book
>>>> 3 where publisher_code, type in
>>>> 4 (select publisher_code, type
>>>> 5 from book
>>>> 6 group by publisher_code, type
>>>> 7 having count(*) > 1);
>>>> where publisher_code, type in
>>>> *
>>>> ERROR at line 3:
>>>> ORA-00920: invalid relational operator
>>>>
>>>>
>>>> SQL> select title
>>>> 2 from book
>>>> 3 where publisher_code and type in
>>>> 4 (select publisher_code, type
>>>> 5 from book
>>>> 6 group by publisher_code, type
>>>> 7 having count(*) > 1);
>>>> where publisher_code and type in
>>>> *
>>>> ERROR at line 3:
>>>> ORA-00920: invalid relational operator
>>>>
>>>> is this what you were referring too? still not being able to get it.
>>>> I am thinking that i have to be half way to the solution with the first
>>>> part that did bring back the six sets, just cannot figure out how to
>>>> get the book code and titles for each of those six sets?
>>>>
>>>> Again thanks for the help
>>>>
>>>> Jeff
>>>
>>> You want get all pairs of books from your table - to get all
>>> permutations usually cross join is used. If you consider (1,2) to be the
>>> same as (2,1), then all permutations should be reduced about a half - to
>>> achieve it, a simple condition like (j<k) - where j,k are your set
>>> items - is enough. To get your selection restricted only on the same
>>> type and publisher - simply put this restriction into the join
>>> condition. Finally, you can get something like:
>>>
>>> SQL> with books as (
>>> 2 select 'JP' publisher_code,'MYS' type,'The Jupiter Legacy' title
>>> from dual union all
>>> 3 select 'ST','SFI','The Daleth Effect' from dual union all
>>> 4 select 'ST','SFI','A Stainless Steel Rat is Born' from dual union
>>> all
>>> 5 select 'JP','MYS','Galactic Dreams' from dual union all
>>> 6 select 'VB','MYS','The Puppet Masters' from dual union all
>>> 7 select 'LB','FIC','The Stainless Steel Rat' from dual union
>>> all
>>> 8 select 'PE','FIC','One Step from Earth' from dual union all
>>> 9 select 'PL','FIC','Planet of No Return' from dual union all
>>> 10 select 'VB','FIC','The Technicolor Time Machine' from dual union
>>> all
>>> 11 select 'LB','FIC','A Rebel in Time' from dual union all
>>> 12 select 'PE','FIC','Skyfall' from dual union all
>>> 13 select 'PL','FIC','War With the Robots' from dual union all
>>> 14 select 'VB','FIC','Stainless Steel Visions' from dual union
>>> all
>>> 15 select 'ST','FIC','The Menace from Earth' from dual
>>> 16 )
>>> 17 -- End test data
>>> 18 select a.publisher_code,a.type,a.title,b.title
>>> 19 from books a,books b
>>> 20 where a.publisher_code=b.publisher_code
>>> 21 and a.type=b.type
>>> 22 and a.title<b.title
>>> 23 /
>>>
>>> PU TYP TITLE TITLE
>>> -- --- ----------------------------- -----------------------------
>>> JP MYS Galactic Dreams The Jupiter Legacy
>>> ST SFI A Stainless Steel Rat is Born The Daleth Effect
>>> LB FIC A Rebel in Time The Stainless Steel Rat
>>> VB FIC Stainless Steel Visions The Technicolor Time Machine
>>> PE FIC One Step from Earth Skyfall
>>> PL FIC Planet of No Return War With the Robots
>>>
>>> 6 rows selected.
>>>
>>> If you like to have all your titles in one column, then it'll look like
>>>
>>> select a.publisher_code,a.type,a.title
>>> from books a,books b
>>> where a.publisher_code=b.publisher_code
>>> and a.type=b.type
>>> -- and a.title<b.title
>>>
>>> Best regards
>>>
>>> Maxim
>>
>> Hi Maxim,
>>
>> Thank you very much this is very close to what I am looking for. I was
>> thinking that I needed to do a self join on the table somehow just was
>> not sure how to do it. I like the way that your table was listed:
>>
>> PU TYP TITLE TITLE
>>> -- --- ----------------------------- -----------------------------
>>> JP MYS Galactic Dreams The Jupiter Legacy
>>> ST SFI A Stainless Steel Rat is Born The Daleth Effect
>>> LB FIC A Rebel in Time The Stainless Steel Rat
>>> VB FIC Stainless Steel Visions The Technicolor Time Machine
>>> PE FIC One Step from Earth Skyfall
>>> PL FIC Planet of No Return War With the Robots
>>
>> Mine did not come out listed that away? here is how mine came out what
>> do I need to do to get it to look like your table?
>>
>> SQL> select a.publisher_code,a.type,a.title,b.title
>> 2 from book a, book b
>> 3 where a.publisher_code=b.publisher_code
>> 4 and a.type=b.type
>> 5 and a.title<b.title
>> 6 order by a.type, a.publisher_code;
>>
>> PU TYP TITLE
>> -- --- ----------------------------------------
>> TITLE
>> ----------------------------------------
>> LB FIC Franny and Zooey
>> Nine Stories
>>
>> LB FIC Franny and Zooey
>> The Catcher in the Rye
>>
>> LB FIC Nine Stories
>> The Catcher in the Rye
>>
>>
>> PU TYP TITLE
>> -- --- ----------------------------------------
>> TITLE
>> ----------------------------------------
>> PE FIC East of Eden
>> Of Mice and Men
>>
>> PE FIC East of Eden
>> The Grapes of Wrath
>>
>> PE FIC Of Mice and Men
>> The Grapes of Wrath
>>
>>
>> PU TYP TITLE
>> -- --- ----------------------------------------
>> TITLE
>> ----------------------------------------
>> PL FIC Beloved
>> Jazz
>>
>> PL FIC Jazz
>> Song of Solomon
>>
>> PL FIC Beloved
>> Song of Solomon
>>
>>
>> PU TYP TITLE
>> -- --- ----------------------------------------
>> TITLE
>> ----------------------------------------
>> VB FIC The Fall
>> The Stranger
>>
>> JP MYS Slay Ride
>> The Edge
>>
>> ST SFI Harry Potter and the Goblet of Fire
>> Harry Potter and the Prisoner of Azkaban
>>
>>
>> 12 rows selected.
>>
>> Thanks again for all the help from everyone.
>>
>> Jeff
>>
>
> Note, please, the approach which Charles suggested, should work for you
> too, you had only one small syntax mistake. Correct query would look like
>
> select title
> from book
> where (publisher_code,type) in
> (select publisher_code, type
> from book
> group by publisher_code, type
> having count(*) > 1);
>
> You have to choose, which sql is more suitable for your needs and probably
> make some performance benchmarking.
>
> Best regards
>
> Maxim
LOL writing this while I slap myself upside the head. It is always the
small things that will get you. I could not find a good example of the IN
clause everyone i found only had one column listed before the IN statement
so I did not realize that I need the parenthsis around the 2 columns before
the IN clause. After making that correction here is how it now looks:
SQL> select book_code, title, publisher_code, type
2 from book
3 where (publisher_code,type) in
4 (select publisher_code, type
5 from book
6 group by publisher_code, type
7 having count(*) > 1);
BOOK TITLE PU TYP
---- ---------------------------------------- -- ---
9882 Slay Ride JP MYS
0808 The Edge JP MYS
9883 The Catcher in the Rye LB FIC
6908 Franny and Zooey LB FIC
3743 Nine Stories LB FIC
9701 The Grapes of Wrath PE FIC
7405 East of Eden PE FIC
2766 Of Mice and Men PE FIC
9627 Song of Solomon PL FIC
6128 Jazz PL FIC
138X Beloved PL FIC
BOOK TITLE PU TYP
---- ---------------------------------------- -- ---
7443 Harry Potter and the Goblet of Fire ST SFI
2226 Harry Potter and the Prisoner of Azkaban ST SFI
7559 The Fall VB FIC
0200 The Stranger VB FIC
15 rows selected.
so this brings back the same results as the code you also had :) although I
do think I like the way yours formatted with the PU TYPE the each title all
listed in one row .
PU TYP TITLE TITLE
-- --- ----------------------------- -----------------------------
JP MYS Galactic Dreams The Jupiter Legacy
ST SFI A Stainless Steel Rat is Born The Daleth Effect
LB FIC A Rebel in Time The Stainless Steel Rat
VB FIC Stainless Steel Visions The Technicolor Time Machine
PE FIC One Step from Earth Skyfall
PL FIC Planet of No Return War With the Robots
Again Thanks too both for the input I having been working on this for a few
hours now. plus also glad too see that atleast I was on the right track
myself just missing the correct syntax to make it work.
Jeff
Received on Sun Nov 25 2007 - 11:45:58 CST
