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Re: SQL-statement

From: Chet Justice <chet.justice_at_pfsf.org>
Date: 21 Apr 2005 16:53:53 -0700
Message-ID: <1114122052.142829.64060@o13g2000cwo.googlegroups.com>


One other way:

SELECT
  a.id,
  a.name,
  COUNT(CASE WHEN b.active = 1 THEN 1 ELSE NULL END) active,   COUNT(CASE WHEN b.active = 0 THEN 1 ELSE NULL END) not_active FROM
  company a,
  employee b
WHERE a.id = b.compid (+)
GROUP BY
  a.id,
  a.name Received on Thu Apr 21 2005 - 18:53:53 CDT

Original text of this message

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