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Re: Help with SQL

From: Prince Of Thieves <thief_NOSPAM_at_hotmail.com>
Date: Tue, 20 Jan 2004 12:34:37 +1100
Message-ID: <Iw%Ob.47$Jc6.935@nnrp1.ozemail.com.au>


Sorry, I had the tables "STYLEC, REFCODE" in the SQL when they were not being used.

-- 

Prince Of Thieves



"Prince Of Thieves" <thief_NOSPAM_at_hotmail.com> wrote in message
news:yu%Ob.46$Jc6.1664_at_nnrp1.ozemail.com.au...

> I have the following SQL:
>
> SELECT DISTINCT STYLE.STYLEIDX, STYLE.STYLECODE, STYLE.NAME, STYLE.DESCRIP
> FROM STYLE
> WHERE STYLE.REF5 = 2054
> AND STYLE.ACTIVE = 1
> ORDER BY 2;
>
> The 2054 value comes from another table, called REFCODE, which looks like
> this:
>
> RGIDX RCIDX CODE NAME RPCIDX ACTIVE
> 1046 1975 NHL Nhl 348 1903 1
> 1046 1936 NON LICENSED Non Licensed 1914 1
> 1046 2054 NON-LICENSED Non-Licensed 1914 1
>
>
> The SQL to get the above is:
>
> SELECT DISTINCT *
> FROM REFCODE
> WHERE RGIDX = 1046 AND ACTIVE = 1
> ORDER BY 1;
>
> Instead of using "WHERE STYLE.REF5 = 2054" in the top-most SQL, I want to
> search by the CODE, ie. "NON-LICENSED". So I changed the SQL to:
>
> SELECT DISTINCT STYLE.STYLEIDX, STYLE.STYLECODE, STYLE.NAME, STYLE.DESCRIP
> FROM STYLE, STYLES, STYLEC, REFCODE
> WHERE STYLE.REF5 = (SELECT RCIDX FROM REFCODE WHERE RGIDX = 1046 AND
> REFCODE.CODE = 'NON-LICENSED')
> AND STYLE.ACTIVE = 1
> ORDER BY 2;
>
> Note that "(SELECT RCIDX FROM REFCODE WHERE RGIDX = 1046 AND REFCODE.CODE
=
> 'NON-LICENSED')
> " returns 2054 only.
>
> The problem is that the query now seems to "hang". The original (top-most)
> query runs instantly). Have I done this correctly?
>
>
> --
>
> Prince Of Thieves
>
>
>
>
Received on Mon Jan 19 2004 - 19:34:37 CST

Original text of this message

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