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Re: Is there a better way than two "exists" and a union?

From: Stephan Bressler <stephan.bressler_at_pdb.sbs.de>
Date: Fri, 15 Mar 2002 13:36:01 +0100
Message-ID: <a6spra$ete$1@news.mch.sbs.de> 





Hi Gary,



maybe a outer join will do. Try



select top_id, decode(childoftop.ct_id, NULL, 'NO','YES')
from top, childoftop


where top.top_id = childoftop.top_id (*)



Regards


Stephan
Received on Fri Mar 15 2002 - 06:36:01 CST












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