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Re: Using a MIN with a COUNT

From: <lily99_at_my-deja.com>
Date: Tue, 23 Nov 1999 19:23:24 GMT
Message-ID: <81epj7$btf$1@nnrp1.deja.com>


I think you can try this way:

    SELECT COUNT(nbDesks), nbDesks
    FROM rooms
    GROUP BY (nbDesks)
    HAVING COUNT(nbDesks) = MIN(COUNT(nbDesks))     ORDER BY 1; Hope this will help.

In article <C_x_3.1088$ym.59835_at_wagner.videotron.net>,   "martinl" <laflamme_at_iname.com> wrote:
> Greetings to all,
>
> I have a small question regarding the combined use of the MIN
and COUNT
> set functions. I have a querry which looks like this:
>
> SELECT COUNT(nbDesks), nbDesks
> FROM rooms
> GROUP BY (nbDesks)
> ORDER BY 1;
>
> This will return the following results:
>
> COUNT(NBDESKS) NBDESKS
> -------------- --------------------
> 2 d2
> 3 d1
> 3 d4
> 4 d3
>
> Now, using the COUNT(nbDesks) column as a referrence, I would
like to
> retrieve only the min value of this table, i.e the first line. My
> question is: is there any way to use the MIN function with the COUNT
> function to achieve this? As a first try, I attempted to combine
them in
> the following
> way:
>
> SELECT MIN(COUNT(nbDesks)), nbDesks
> FROM rooms
> GROUP BY (nbDesks)
> ORDER BY 1;
>
> But that didn't work. Anybody has an idea? I know I could use a
cursor
> to retrieve the first row but I was wondering if there was a more
direct way
> to do this.
>
> Thanks a lot,
> Martin
>
>

Sent via Deja.com http://www.deja.com/
Before you buy. Received on Tue Nov 23 1999 - 13:23:24 CST

Original text of this message

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