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Re: SQL HELP

From: Philippe <parnaud_at_yahoo.com>
Date: 21 Aug 1998 06:43:32 GMT
Message-ID: <01bdccce$f9f9f840$2a822c95@pdcpm>


Use the TRUNC function :

select count(order_id), trunc(order_date) from order_record
where trunc(order_date) > date1
and trunc(order_date) < date2
group by trunc(order_date);

HTH Min Wang <mwang_at_colorbank.com> wrote in article <35DCB6BF.46B891E7_at_colorbank.com>...
> Hi:
>
> I have a query like this:
>
> select count(order_id), order_date
> from order_record
> where order_date > date1
> and order_date < date2
> group by order_date;
>
>
> What I want is get the numbers of orders for each day from date1 to
> date2.
> But what I get is a individaul order list instead of the sum of order of
> each day. I guess this may be because I used sysdate when I record the
> orders. Some orders might be placed in the same day but at different
> time.
>
> My question is how I can get count(order_id) for each day?
>
> Thanks.
>
Received on Fri Aug 21 1998 - 01:43:32 CDT

Original text of this message

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