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Re: Very Simple SQL question ... hepl ? ...

From: Chinna <jchinna_at_enron.com>
Date: 1997/09/22
Message-ID: <01bcc75c$215887e0$06f7fb9b@eoghou1325.eog.enron.com>#1/1

You expected output will appear with this query::

select distinct a.lastname,count(*)
from names a, names b
where a.rowid <> b.rowid
and a.lastname=b.lastname
group by a.n

Let me know if this helped.

Chinna

Anon <pjbump_at_i1.net> wrote in article
<01bcc5e8$e8e46ce0$d33ae6cf_at_default>...
> SELECT A.last_name, A.pid
> FROM tablex A, tablex B
> WHERE A.last_name = B.last_name
> and A.rowid <> B.rowid;
> --
> Phillip Bump
> Senior Principal Consultant
> Oracle Consulting
>


> -----------------------------------------------------------------------
> The opinions expressed are my own and do not necessarily reflect those of
> Oracle Corporation
>
> Hank Griffioen <hank_at_daac.gsfc.nasa.gov> wrote in article
> <34201C6E.CF4C987B_at_daac.gsfc.nasa.gov>...
> > I have a table called names that has last_name and pid in
> > the table. I am tryint to find a simple query that
> > will all me to select all rows that have duplicated last names.
> >
> > For example
> >
> > last_name pid
> > --------------------------
> > smith 1
> > smith 3
> > jones 4
> > griffin 5
> > stevens 6
> > stevens 7
> >
> > I want to do the opposite of distinct.
> >
> > something like ....
> > select duplicate last_name pid from person.
> >
> > smith 1
> > smith 3
> > stevens 6
> > stevens 7
> >
> >
> > --
> > Hank Griffioen CFII,MEII,AGI,IGI INTERNET:
> > hank_at_daacdev1.nasa.gsfc.gov
> > GSFC BLD 32 Code 902.2 fax 614-5304
> > Greenbelt, MD 20770 Phone: 301-614-5488
> > To order CD-ROMs and data URL = http://daac.gsfc.nasa.gov/
> > NASA Goddard Flying Club URL = http://daac.gsfc.nasa.gov/NGFC/
> > (***I do not speak for HSTX, NASA or NASA Goddard Flying Club***)
> >
>
  Received on Mon Sep 22 1997 - 00:00:00 CDT

Original text of this message

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