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Re: Interview Question

From: Jeremy Rickard <Jeremy_at_jbdr.demon.co.uk>
Date: 1997/06/13
Message-ID: <+slTcNA2qZozEwgn@jbdr.demon.co.uk>#1/1

>I would answer:
>
>1. weigh 3 against 3. If they balance then weigh the remaining two against
> each other to find the heavier marble. If one set of three is heavier,
> then take 2 of those three and weigh them. If they balance, then the
> heavier marble is the 1 remaining, otherwise the heavier one is it.

  1. Very good. And no tricks after all! -- Jeremy Rickard
Received on Fri Jun 13 1997 - 00:00:00 CDT

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