RE: conditional 'order by'

From: Mark W. Farnham <mwf_at_rsiz.com>
Date: Fri, 19 Dec 2008 13:47:11 -0500
Message-ID: <5A822D58E06F4D278206DC3D07E5FA4E@rsiz.com>


You've got me really confused. Are F, 0, H, 1, and 2 the names of columns?  

If so, how many columns that are candidates to order by do you have?  

Are you intending to generate queries to execute or did I miss the memo on a new syntax involving order by?  

Regards,  

mwf  


From: oracle-l-bounce_at_freelists.org [mailto:oracle-l-bounce_at_freelists.org] On Behalf Of Eugene Pipko
Sent: Friday, December 19, 2008 11:57 AM To: 'oracle-l_at_freelists.org'
Subject: conditional 'order by'  

Hi all,

I have a query that needs to be ordered by based on the second letter of the code passed in it.

For instance if the code is '9F9Q' then I'd order by 'F' , then by 'H', then by any other.

If the code is '7H7Q' then I'd order by 'H', then by 'F', then by any other.

I know that I can do it in 2 steps, but is it possible to do in one sql statement?  

Select .

From .

Where ..

If substr(code,2,1)='F' then

                Order by decode(code,'F',0,'H',1,2);

Elsif substr(code,2,1)='H' then

                Order by decode(code,'H',0,'F',1,2);

End if;    

Thanks,    

Eugene

P Please consider the environment before printing this e-mail.  

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Received on Fri Dec 19 2008 - 12:47:11 CST

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