RE: Convert Long to Date

From: Brady, Mark <Mark.Brady_at_Constellation.Com>
Date: Thu, 26 Jun 2008 16:27:27 -0400
Message-ID: <72AB68B424526641A8514835270C2EB502D0D07B@EXM-OMF-21.Ceg.Corp.Net>

SO Pl/sql subtr will take a long but SQL substr does not.

begin

        for p in (SELECT * FROM user_tab_partitions) loop    

           DBMS_OUTPUT.Put_line(substr(p.high_value, 1, p.high_value_length));        

        end loop;

end;

Works fine but

SELECT substr(p.high_value, 1, p.high_value_length) FROM user_tab_partitions p

Does not. That's my problem.

---

From: Tim Gorman [mailto:tim_at_evdbt.com] Sent: Thursday, June 26, 2008 4:16 PM
To: Brady, Mark
Cc: oracle-l-freelists
Subject: Re: Convert Long to Date

Mark,

This is embedded deep within a couple thousand lines of PL/SQL package code posted on the internet.  The package is named EXCHPART, the procedure is called ADD_NEWER_THAN, and its URL is http://www.EvDBT.com/exchpart.sql.  Here it is excerpted into pseudo-PL/SQL... procedure add_newer_than ...
    ...
    v_errcontext      varchar2(500);
    v_high_value      varchar2(100);
    v_day             date;
    type cType        is ref cursor;
    c                 cType;
    ...
    cursor get_partition_info ...

    is


    select            ...,

                      high_value,

                      high_value_length,

                      ...
    from              all_tab_partitions
    ...;

begin
...
for p in get_partition_info ... loop
    ...
    v_high_value := substr(p.high_value, 1, p.high_value_length);
    v_errcontext := 'select ' || v_high_value || ' from dual';
    open c for v_errcontext;
    fetch c into v_day;
    close c;
    ...

end loop;
...
end;
/
So the end result is that the variable "v_day" has the value from HIGH_VALUE...

Hope this helps...

Tim Gorman
consultant - Evergreen Database Technologies, Inc. P.O. Box 1802, Evergreen CO 80437-1802

website   = http://www.EvDBT.com/
email     = Tim_at_EvDBT.com
mobile    = +1-303-885-4526
fax       = +1-303-484-3608
Yahoo IM  = tim_evdbt

Brady, Mark wrote:
Oracle stores the High Value of a Partition in a Long column. I swear I've searched the friendly web, and I just can't figure out how to get this long column converted back to a date or char I can take a char to a date. If it exists on the web, please tell me. I don't know why this is so hard to find. >>> This e-mail and any attachments are confidential, may contain legal, professional or other privileged information, and are intended solely for the addressee. If you are not the intended recipient, do not use the information in this e-mail in any way, delete this e-mail and notify the sender. CEG-IP2   

--
http://www.freelists.org/webpage/oracle-l

Received on Thu Jun 26 2008 - 15:27:27 CDT