RE: RDA - Top SQL report

Hmm...interesting...I've never looked at this report......my guess would be that they are speculating that a disk read takes about 20 ms, so, disk_reads/50 would give you seconds. Same idea for buffer_gets. If a buffer get takes 2 ms, then buffer_gets/500 will yield seconds.

As to how accurate that conversion is, well, that depends on way too much stuff to speculate on.....

-Mark

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Mark J. Bobak
Senior Oracle Architect
ProQuest Information & Learning

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-----Original Message-----

From: oracle-l-bounce_at_freelists.org
[mailto:oracle-l-bounce_at_freelists.org] On Behalf Of Srikanth Kalluri Sent: Wednesday, March 01, 2006 6:11 PM
To: Oracle-L Freelists
Subject: RDA - Top SQL report

Hi,  

The question is regarding (Remote Diagnostics Assistant; Metalink Note: 314422.1) Oracle Support provides to troubleshoot performance issues in a database {RDA} and the calculation of the "Top SQL Report"  

More specifically, I am curious how the following ratios are deemed "Expected Respose Time (in Seconds)"  

From v$sqlarea:
 { (disk_reads/executions)/50 }
 { (buffer_gets/executions)/500 }  

Also, what is the significance of the numbers 50 and 500 respectively?  

Queries used in the report:  

select
 sql_text,
 executions,
 disk_reads / decode(executions,0,1, executions) / 50 from v$sqlarea where disk_reads / decode(executions,0,1, executions) / 50 > 100 order by executions desc;

select
 sql_text,
 executions,
 buffer_gets / decode(executions,0,1, executions) / 500 from v$sqlarea where buffer_gets/ decode(executions,0,1, executions) / 500 > 100 order by executions desc;  

Thanks,
Sri    

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http://www.freelists.org/webpage/oracle-l Received on Wed Mar 01 2006 - 17:35:12 CST