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Re: print horizontal

From: Enrique Fernandez-Pampillon <oracle.pampillon_at_gmail.com>
Date: Tue, 24 Jan 2006 12:15:02 +0100
Message-ID: <7ba974f50601240315o5c1a1f5er14a45eae12b99229@mail.gmail.com>


I think this could be useful:

SQL> create table my_test_table2 (y number(2), x number(5));

Table created.

SQL> insert into my_test_table2 select 1, rownum from all_objects where rownum < 7;

6 rows created.

SQL> insert into my_test_table2 select 2, rownum from all_objects where rownum < 10;

9 rows created.

SQL> select * from my_test_table2;

         Y X
---------- ----------

         1          1
         1          2
         1          3
         1          4
         1          5
         1          6
         2          1
         2          2
         2          3
         2          4
         2          5
         2          6
         2          7
         2          8
         2          9

15 rows selected.

SQL> column trans format a80
SQL> r
  1 select y, max(sys_connect_by_path(x, ' | ')) trans   2 from (
  3 select y, x, row_number() over (partition by y order by x) cur, row_number() over (partition by y order by x) - 1 prev   4 from my_test_table2
  5 )
  6 connect by prior cur = prev and prior y = y   7 start with cur = 1
  8* group by y

         Y TRANS



         1  | 1 | 2 | 3 | 4 | 5 | 6
         2  | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9


HTH On 1/24/06, raja rao <raja4list_at_yahoo.com> wrote:
>
> HI Team,
>
> Can someone help me to print the below in horizontal.
>
> SQL> select * from v2h;
> X
> ----------
> 1
> 2
> 3
> 4
> 5
>
>
> I need the values tobe printed like this:
>
> 1 2 3 4 5
>
> can someone give me some clue on this without using pl/sql.
>
> Thanks in adv,
> Raj
>
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--
------------------------------------------------
Enrique

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Received on Tue Jan 24 2006 - 05:15:02 CST

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