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RE: Update of Clobs *Performance*

From: Mark W. Farnham <mwf_at_rsiz.com>
Date: Wed, 3 Nov 2004 15:00:03 -0500
Message-ID: <KNEIIDHFLNJDHOOCFCDKOEHHFJAA.mwf@rsiz.com>


create index why_full_scan_all_my_clobs_for_each_one_row_update on tableB(tabB_num)

change your where clause to where tabB_num = to_number(v_id)

Think about a commit counter within the loop less than the entire table. Maybe 1000 or 10000?

Regards,

mwf

-----Original Message-----

From: oracle-l-bounce_at_freelists.org
[mailto:oracle-l-bounce_at_freelists.org]On Behalf Of Mike Schmitt Sent: Wednesday, November 03, 2004 2:29 PM To: oracle-l_at_freelists.org
Subject: Update of Clobs *Performance*

Hi all,

I have a developer who is trying to use PL/SQL to update all of the CLOBS of a specific table (nightly basis). I am looking for advice on how to speed up the performance for this process. SQL tracing the process shows the following before I cancel out.

call count cpu elapsed disk query current rows
------- ------ -------- ---------- ---------- ----------

Thanks

Table_A (141,000 rows, no indexes)
tabA_char VARCHAR2(10)
tabA_clob CLOB

Table_B (145,000 rows, no indexes)
tabB_num number
tabB_clob CLOB

Procedure
declare
v_clob varchar2(32500);
v_id varchar(10);

cursor cont_rep_clob is
select tabA_char, tabA_clob
from Table_A;

begin
open cont_rep_clob;
loop
fetch cont_rep_clob into v_id, v_clob;

exit when cont_rep_clob%NOTFOUND;

update Table_B
set tabB_clob = v_clob
where to_char(tabB_num) = v_id;

commit;

end loop;
close cont_rep_clob;

--

http://www.freelists.org/webpage/oracle-l

--

http://www.freelists.org/webpage/oracle-l Received on Wed Nov 03 2004 - 13:57:06 CST

Original text of this message

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