RE: displaying result sets in the order listed in the IN list

From: Khedr, Waleed <Waleed.Khedr_at_FMR.COM>
Date: Fri, 16 Apr 2004 14:23:00 -0400
Message-ID: <42BBD772AC30EA428B057864E203C999113EB6@MSGBOSCLF2WIN.DMN1.FMR.COM>

This should work most of the time if the column is indexed:

create table test_ordered_in ( c1 number primary key, c2 number);

insert into test_ordered_in values (1,2);=20
insert into test_ordered_in values (2,5);
insert into test_ordered_in values (3,0);
insert into test_ordered_in values (4,9);
insert into test_ordered_in values (5,7);

select =20
 *
 from test_ordered_in
 where c1 in (1,3,4)

C1	C2
4	9
3	0
1	2

select --+ index(test_ordered_in, ) =20
 *
 from test_ordered_in
 where c1 in (1,3,4)

C1	C2
1	2
3	0
4	9

They idea is to do inlist iterator using the index.

Regards,

Waleed

-----Original Message-----

From: Ivan Chow [mailto:ichow2_at_hotmail.com] Sent: Friday, April 16, 2004 1:35 PM
To: oracle-l_at_freelists.org
Subject: displaying result sets in the order listed in the IN list

Hello,
I have a table that has the following values:

select * from mytab;

mycol

---

1
2
3
4
5
6

select * from mytab where mycol in (3,1,4);

mycol

---

1
3
4

Is it possible to display the values of mycol in the order the literal=20 values are listed in the IN list? The IN list string 3,1,4 is passed in = by=20
another program and it can be listed in any order. I need the results to = be=20
display in whatever the order is in the IN list.

My expected result is

mycol

---

3
1
4

Is that possible? If not, any suggestions?

thanks in advance.

Ivan C.

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Received on Fri Apr 16 2004 - 13:19:33 CDT