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RE: SQL to retrieve all distinct records

From: Jocke Treugut <treugut_tuning_at_yahoo.se>
Date: Thu, 15 Apr 2004 20:04:01 +0200
Message-ID: <DIEEJKEHHCNMMKMBNAKDEEAPCBAA.treugut_tuning@yahoo.se>


Hi, Alison!

I guess it depends on which row you want to show of all rows that have the same A and B. Do you wanna show the one with first ROWID or ...???

Cheers / Jocke Treugut

www.treugut-tuning.com

-----Original Message-----
From: oracle-l-bounce_at_freelists.org
[mailto:oracle-l-bounce_at_freelists.org]On Behalf Of Alison Barak Sent: den 15 april 2004 17:24
To: oracle-l_at_freelists.org
Subject: RE: SQL to retrieve all distinct records

I believe I have found a solution. Just wonder if anyone else has an alternative or better approach?

select * from testing where rowid in (select min(rowid) from testing group by a,b);

thanks.

alison

>From: "Alison Barak" <ambarak_at_hotmail.com>
>To: oracle-l_at_freelists.org
>Subject: SQL to retrieve all distinct records
>Date: Thu, 15 Apr 2004 09:38:28 -0400
>
>Hi,
>can someone assist me with formulating a query to retrieve all distinct
>records. I need to retrieve all three columns a,b &c based on the distinct
>of the two columns a & b.
>
>SQL> select * from testing;
>A B C
>---------- ---------- ----------
>APPS APPS R1
>SYS SYS2 R2
>SYS SYS2 R3
>DOC DOC2 R4
>DC DC2 R5
>DOC DOC R6
>
>The result should be
>A B C
>---------- ---------- ----------
>APPS APPS R1
>SYS SYS2 R2
>DOC DOC2 R4
>DC DC2 R5
>DOC DOC R6
>
>
>I tried using group by/having count but was not successful. Any idea?
>
>Thanks.
>
>alison
>



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Received on Thu Apr 15 2004 - 14:03:27 CDT

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