RE: update year in date column

From: Khedr, Waleed <Waleed.Khedr_at_FMR.COM>
Date: Tue, 23 Mar 2004 16:11:37 -0500
Message-ID: <D91D9D5A73FC694BBC52F1EB26AD410F02412098@MSGBOSCLD2WIN.DMN1.FMR.COM>

It's 100 years equals 1200 months.
Use add_month(<column>, -1200)

Waleed

-----Original Message-----

From: Barbara Baker [mailto:barbarabbaker_at_yahoo.com] Sent: Tuesday, March 23, 2004 3:01 PM
To: oracle-l_at_freelists.org
Subject: update year in date column

OK, I'm just going to bite the bullet and claim total ignorance here and see if someone takes pity on me :( (sad face a nice touch, eh?)

Someone has accidently updated 378 records in the customer table. The date changed from 1999 to 2099. I need to change just the year back to 1999 for these records. (I'd like to keep the time stamp, if possible. The month and day are correct.) I looked on metalink, google, and asktom. Some nice examples, but not what I really need.

Thought I'd be clever and subtract 1000 from the date. This works, but I don't know how to get it formatted back into a date.

I'd prefer just sqlplus, but will use pl/sql if necessary.

Here's what I've done so far:
(solaris 9 oracle 9.2.0.4)

JServer Release 9.2.0.4.0 - Production

DOC> CUSNO CUSNAME CRDATE

DOC>---------- -----------------------------------


----------

DOC>    798489 GILBERT, ROSS                      
09/16/2099
DOC>    826744 HOEFLER, MATT                      
10/08/2099
DOC>    795126 FORT,  JOETTA

09/08/2099
DOC>*/ SQL>
SQL> ---select to_date(to_char(crdate,'MM/DD/YYYY')) from customer where cusno=798489;

SQL> ---update advdb.custtest_barb
SQL>  ---set crdate= to_char(crdate,'MM/DD/YYYY'))
SQL> ---from customer where cusno=798489;
SQL> 
SQL> select
to_date(to_char(crdate,'ddmmyyyy')-1000),'MM/DD/YYYY')
  2     from customer where cusno=798489;

select
to_date(to_char(crdate,'ddmmyyyy')-1000),'MM/DD/YYYY')

ERROR at line 1:
ORA-00923: FROM keyword not found where expected

SQL> 
SQL> 
SQL> --- these both work
SQL> select to_char(crdate,'ddmmyyyy')  from

custtest_barb where cusno=798489;

TO_CHAR(

16092099

SQL> select to_char(crdate,'ddmmyyyy') - 1000 from custtest_barb where cusno=798489;

TO_CHAR(CRDATE,'DDMMYYYY')-1000

16091099

Thank for any assistance.

Barb

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Received on Tue Mar 23 2004 - 15:47:21 CST