Oracle-L: RE: Silly SQL Question

From: Alan Gano <Alan.Gano_at_Banfield.net>
Date: Mon, 17 Nov 2003 13:29:36 -0800
Message-ID: <F001.005D6F3C.20031117132936@fatcity.com>

Gabriel,

How about this untested code?

Alan.

select

usr
from

(

      select
         usr,
         sum(decode(val,1,1,0)) look1,  -- flag for 1
         sum(decode(val,5,5,0)) look2,  -- flag for 5
         sum(decode(val,7,7,0)) look3,  -- flag for 7
         sum(decode(val,1,0,5,0,7,0,1)) look4  -- flag for others
      from the_table
      group by usr

)
where

   look1 = 1 AND
   look2 = 1 AND
   look3 = 1 AND
   look4 = 0

-----Original Message-----
Sent: Thursday, November 13, 2003 2:05 PM To: Multiple recipients of list ORACLE-L

I have a table with like this:

Usr val

GAP 1
GAP 5
GAP 7
JKL 8
JKL 5 I need a query that returns the user (GAP o JKL) that has ALL the values in a list. Example: Having the list: 1,5,7 the result will be GAP, but with the values 1,5 or 1,5,7,8 there will be no result.

select distinct usr
from xxx
where val = All (1,3,5)

I was trying the ALL operator but it works with part of the list, I need the user that has (exactly) all the values in the list. Any idea?

Maybe it's a simple solution, but after several hours I feel blocked.

TIA
Gabriel

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Author: Gabriel Aragon
INET: gabriel_gap_at_yahoo.com

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Author: Alan Gano
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