Oracle-L: RE: Silly SQL Question

From: Aponte, Tony <AponteT_at_hsn.net>
Date: Thu, 13 Nov 2003 14:29:40 -0800
Message-ID: <F001.005D698B.20031113142940@fatcity.com>

Here's one solution.

SELECT
usr
FROM
xxx
GROUP BY
usr
HAVING
SUM(DECODE(val,1,1,0)) > 0
AND
SUM(DECODE(val,5,1,0)) > 0
AND
SUM(DECODE(val,7,1,0)) > 0

HTH
Tony Aponte

-----Original Message-----
Sent: Thursday, November 13, 2003 5:05 PM To: Multiple recipients of list ORACLE-L

I have a table with like this:

Usr val

GAP 1
GAP 5
GAP 7
JKL 8
JKL 5 I need a query that returns the user (GAP o JKL) that has ALL the values in a list. Example: Having the list: 1,5,7 the result will be GAP, but with the values 1,5 or 1,5,7,8 there will be no result.

select distinct usr
from xxx
where val = All (1,3,5)

I was trying the ALL operator but it works with part of the list, I need the user that has (exactly) all the values in the list. Any idea?

Maybe it's a simple solution, but after several hours I feel blocked.

TIA
Gabriel

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Author: Gabriel Aragon
INET: gabriel_gap_at_yahoo.com

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Author: Aponte, Tony
INET: AponteT_at_hsn.net

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