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RE: RE: Which method is more efficient

From: Orr, Steve <sorr_at_rightnow.com>
Date: Wed, 28 May 2003 12:39:46 -0800
Message-ID: <F001.005A4D37.20030528123946@fatcity.com>


And with CTAS you can specify nologging to minimize redo generation. "Cloning" a table, renaming/dropping the source, and renaming the clone to the production table could be interesting. You would have to recreate indexes.

-----Original Message-----
Sent: Wednesday, May 28, 2003 1:35 PM
To: Multiple recipients of list ORACLE-L

Bryan,

Can you ...
create table my_work_table as
select * from changed_parts_table
minus
select * from existing_parts_table
/

The result will give you all the rows where _something_ is different between your existing table and changed table. This will cut down a lot on your processing. Afterwards, you can drop the my_work_table.

Raj



Rajendra dot Jamadagni at nospamespn dot com All Views expressed in this email are strictly personal. QOTD: Any clod can have facts, having an opinion is an art !

-----Original Message-----
Sent: Wednesday, May 28, 2003 2:40 PM
To: Multiple recipients of list ORACLE-L

The fields that are changed are determined by

1) A loop would start until all records in parts change table are done 
2) Select a part record from the part changes table 
3) Select the same part from the existing part table 
4) Compare the value in the parts changes table against the corresponding 
field in the part table 5) After comparing all fields in the records, create record in a seperate work table with the values populated with null if the field values matched and the new value if the values did not. 6) This loop would continue until all parts are done. 7) After any records in the work table where all fields (outside of part number) are null are deleted.

This process normally will decrease the number of records to be processed after this point by 75%.

Hope that helps,

Bryan

-----Original Message-----
Sent: Wednesday, May 28, 2003 1:21 PM
To: Multiple recipients of list ORACLE-L

oh i missed part of it. the question is how do you figure out which fields have changed? if you have to do an anti-join on each field, then do an update of every field.

the question is how will you determine which fields have changed?
>
> From: DENNIS WILLIAMS <DWILLIAMS_at_LIFETOUCH.COM>
> Date: 2003/05/28 Wed PM 12:59:51 EDT
> To: Multiple recipients of list ORACLE-L <ORACLE-L_at_fatcity.com>
> Subject: RE: Which method is more efficient
>
> Bryan - If this is a critical issue, I would try it both ways on a test
> database and use log miner to examine the amount of redo that is
generated.
> My recollection is that you will find that the redo record records the
> before and after data for each field. So just updating all fields may
> generate significantly more redo. But don't trust my recollection on this
> issue, test it yourself.
>
> Dennis Williams
> DBA, 80%OCP, 100% DBA
> Lifetouch, Inc.
> dwilliams_at_lifetouch.com
>
>
> -----Original Message-----
> Sent: Wednesday, May 28, 2003 10:50 AM
> To: Multiple recipients of list ORACLE-L
>
>
> Hello everyone,
>
> I have a question for the group of which method is more efficient.
>
> To set the stage my company has a process to load part changes from
vendors
> into the tables in an 8.1.7.4 Oracle database with archiving on and this
> database has a standby database at disaster recovery site, so nologging is
> not an option.
>
> There is a discussion going on as to which method is more effective for
> updating the information in a table. In looking at effectiveness, I am
> looking at reducing the amount of redo information produced and having the
> database do the least amount of work.
>
> 1) Method 1 is to update the information only for the fields that have
> changed, 1 field at a time.
> 2) Method 2 is to update the information for all the fields in the
> record whether they have changed or not, 1 record at a time.
>
> The size of the record is 1843 bytes and the distribution of field sizes:
> 2 fields varchar2(240).
> 1 field varchar2(150)
> 15 fields varchar2(50)
> 1 field varchar2(3)
> 2 fields varchar2(20)
> 4 fields varchar2(40)
> 3 fields varchar2(1)
> 2 fields varchar2(25)
> 2 fields number(10,2)
> 1 field number(13,2)
> 1 field number(1)
> 1 field number
> 1 field varchar2(6)
> 1 field number (17,2)
> 1 field varchar2(4)
> 3 fields that are date.
>
> In the past couple of months the average number of fields changed per
record
> was 3 to 4 fields per record.
>
> Thanks for your help,
>
> Bryan Rodrigues
> Oracle DBA
> Elcom, Inc.
>
>
> --
> Please see the official ORACLE-L FAQ: http://www.orafaq.net
> --
> Author: Rodrigues, Bryan
> INET: BRodrigues_at_elcom.com
>
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> Author: DENNIS WILLIAMS
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  INET: rgaffuri_at_cox.net 

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Author: Orr, Steve
  INET: sorr_at_rightnow.com

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Received on Wed May 28 2003 - 15:39:46 CDT

Original text of this message

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