Re: awk and ksh question

From: Robert Eskridge <bryny_at_dfweahs.net>
Date: Mon, 03 Feb 2003 15:48:53 -0800
Message-ID: <F001.005428D2.20030203154853@fatcity.com>

Lisa,

Awk and sh are competing for the interpretation of $1. I messed around trying to get the replacement not to happen but didn't have much luck.

Awk is overkill for this anyway. How about:

export FILE=$1
print File is $FILE
for PAGER in `grep -v "^#" $FILE | cut -d" " -f1` do
  print $PAGER
done

-rje

K> Hello everyone,

K> I'm trying to awk through a text file and use that with a passed-in message K> to send email. Here's an example of my text file:

K> # DBA's on call 
K> 9991234567_at_pageme.com    # Lisa pager 
K> lisa.koivu_at_efairfield.com        # Lisa email 

K> Here's my awk statement, which works properly

K> awk '!/^#/ {print $1}' filename.txt

K> prints the first entry in each file and skips any lines starting with #.

K> So I put it in a loop. I don't quite understand all the syntax here, I'm K> pulling the exact syntax out of Steve Adams' database check script.

K> -- 
K> for PAGER in ${*-$(awk '!/^#/ {print $1}' dba_oncall.txt)} 
K> do 

K> print $PAGER

K> done 
K> -- 
K> Works fine. 

K> Now when I try to pass in a parameter in $1 (which I mean to be the email K> message), awk grabs it and the script no longer works. Like this

K> --
K> export FILE=$1

K> print File is $FILE

K> for PAGER in ${*-$(awk '!/^#/ {print $1}' dba_oncall.txt)}; K> do

K> print $PAGER

K> done

-rje

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Author: Robert Eskridge
  INET: bryny_at_dfweahs.net

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