Oracle-L: RE: Partitioning

From: MOORE, Peter Rbh <Peter.MOORE.RBH_at_reading.sema.slb.com>
Date: Tue, 19 Nov 2002 12:11:40 -0800
Message-ID: <F001.005071E3.20021119121140@fatcity.com>

Rishi,

The algorithm for has partitioning in Oracle requires you to choose your partition count as a power of 2 (i.e. 2, 4, 8, 16, 32 partitions, etc) any other number will be unbalanced as you've seen.

Cheers,
Pete

--
Peter Moore
Systems DBA,
Mid-Range Centre of Expertise,
Global Service Delivery,
SchlumbergerSema,
Reading

Phone: 0118 963 6827
Email: pmoore7_at_slb.com




> -----Original Message-----

> From: Rishi.Jain_at_VerizonWireless.com

> [mailto:Rishi.Jain_at_VerizonWireless.com]

> Sent: 19 November 2002 19:39

> To: Multiple recipients of list ORACLE-L

> Subject: Partitioning

> 

> 

> We have a table with around 80 million rows. The table has 

> been partitioned

> by hash as there is no clear way of partitioning depending on 

> range etc..

> The data is very unevenly distributed in these partitions. 

> Some of them even

> have 3 times the number of rows as compared to the other partitions. 

> This application is being ported from Informix to Oracle (9i R2). In

> informix the dba's had partitioned the table based on a 

> function . He was

> taking the mod of the number ( dividing by 10 ) . The values were then

> placed in either of the 10 partitions  ranging from 0 - 9. 

> This really gave

> us very good distribution of data .Can we achieve something 

> similar in 9i

> with list partitioning.

> 

> 

> TIA

> 

> Rishi

> -- 

> Please see the official ORACLE-L FAQ: http://www.orafaq.com

> -- 

> Author: 

>   INET: Rishi.Jain_at_VerizonWireless.com

> 

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-- 
Author: MOORE, Peter Rbh
  INET: Peter.MOORE.RBH_at_reading.sema.slb.com

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Received on Tue Nov 19 2002 - 14:11:40 CST