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RE: SQL Brain Teaser Challenge

From: Jesse, Rich <Rich.Jesse_at_qtiworld.com>
Date: Tue, 05 Nov 2002 13:33:52 -0800
Message-ID: <F001.004FC465.20021105133352@fatcity.com>


Steve,

I'm not sure why as of yet, but I had some success by creating two segmented indexes. One on PARENTID, NODEORDER and the second on NODEORDER, PARENTID:

ID PARENTID NODEORDER DESCRIPTION

1  0        0         top folder
9  1        0         1st subfolder
2  1        1         2nd subfolder
4  2        1         folder 2 item 1
3  2        2         folder 2 item 2
6  2        3         folder 2 item 3
7  1        2         3rd subfolder
5  7        0         folder 3 item 1
8  7        1         folder 3 item 2

Seems strange, though, and I don't have the time to research it. We had the exact same problem for our BOM structures and ended up writing a recursive PL/SQL procedure and cursors to do it. Not nice.

Also, I'm using CBO on 8.1.7.4 and have analyzed the tables and indexes w/o histograms using DBMS_STATS. BTW, the explain plan is a helluva lot better with the indexes... :)

HTH! GL! Rich

Rich Jesse                           System/Database Administrator
Rich.Jesse_at_qtiworld.com              Quad/Tech International, Sussex, WI USA


> -----Original Message-----
> From: Orr, Steve [mailto:sorr_at_rightnow.com]
> Sent: Tuesday, November 05, 2002 11:24 AM
> To: Multiple recipients of list ORACLE-L
> Subject: SQL Brain Teaser Challenge
>
>
> Challenge: present SQL results hierarchically and sort the
> nodes. Use sort
> column without changing data. Here's the DDL/DML to start:
>
> create table treenode (
> id number not null
> constraint pk_treenode primary key,
> parentid number not null,
> nodeorder number not null,
> description varchar2(20) null);
>
> insert into treenode values(1,0,0,'top folder');
> insert into treenode values(9,1,0,'1st subfolder');
> insert into treenode values(7,1,2,'3rd subfolder');
> insert into treenode values(2,1,1,'2nd subfolder');
> insert into treenode values(8,7,1,'folder 3 item 2');
> insert into treenode values(6,2,3,'folder 2 item 3');
> insert into treenode values(5,7,0,'folder 3 item 1');
> insert into treenode values(3,2,2,'folder 2 item 2');
> insert into treenode values(4,2,1,'folder 2 item 1');
> -----------------------------------------------------
> Here's the data presented hierachically without the desired sort:
> select * from treenode
> start with parentid=0 connect by prior id = parentid;
> ID PARENTID NODEORDER DESCRIPTION
> ---------- ---------- ---------- --------------------
> 1 0 0 top folder
> 9 1 0 1st subfolder
> 7 1 2 3rd subfolder
> 8 7 1 folder 3 item 2
> 5 7 0 folder 3 item 1
> 2 1 1 2nd subfolder
> 6 2 3 folder 2 item 3
> 3 2 2 folder 2 item 2
> 4 2 1 folder 2 item 1
> -----------------------------------------------------
> Desired SQL statement results:
> ID PARENTID NODEORDER DESCRIPTION
> ---------- ---------- ---------- --------------------
> 1 0 0 top folder
> 9 1 0 1st subfolder
> 2 1 1 2nd subfolder
> 4 2 1 folder 2 item 1
> 3 2 2 folder 2 item 2
> 6 2 3 folder 2 item 3
> 7 1 2 3rd subfolder
> 5 7 0 folder 3 item 1
> 8 7 1 folder 3 item 2
> -----------------------------------------------------
>
> Kudos to anyone who can figure out how to do this via SQL.
>
>
> Steve Orr
> Bozeman, Montana

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-- 
Author: Jesse, Rich
  INET: Rich.Jesse_at_qtiworld.com

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Received on Tue Nov 05 2002 - 15:33:52 CST

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