Re:

try it:

select
  name
from
  (select c.name, count(p.id) p_count from clients c, projects p    where c.id = p.cl_id
   group by c.name) a,
  (select max(count(id)) p_max from projects     group by cl_id) b
where a.p_count = b.p_max

Regards,
Leszek

At 03:23 2002-09-30 -0800, you wrote:
>Hello all,
>
> I have a query ->
>i have 2 tables -> client and project
>
>fields in project table -> clientid/projectid
>fields in client table -> clientid/name
>
>i want to get the maximum orders one client has got. i mean a project
>having the greatest clients
>how to write it in single query ??
>
>
>like
>project 1 client 1
>project 2 client 1
>project 3 client 2
>
>in the above case, the query should return client ( 1 ).
>
>Thanks and regards,
>Santosh

-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.com
-- 
Author: Leszek Ignaszak
  INET: leszek.ignaszak_at_post.pl

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