RE:

From: Santosh Varma <vsantosh_at_psi.soft.net>
Date: Mon, 30 Sep 2002 21:48:19 -0800
Message-ID: <F001.004DD0CB.20020930214819@fatcity.com>

cannot perform an aggregate function on an expression containing an aggregate or subquery

is the error i am getting while i am executing the query.

SELECT name
FROM (SELECT c.name, COUNT(p.clientid) p_count

      FROM client c, project p
      WHERE c.clientid = p.clientid
      GROUP BY c.name) a,
        (SELECT MAX(COUNT(clientid)) p_max
      FROM project
      GROUP BY clientid) b

WHERE a.p_count = b.p_max

clientid and name are the columns in client table and projectid and clientid are the columns in project table.

santosh

-----Original Message-----
Ignaszak
Sent: Monday, September 30, 2002 6:09 PM To: Multiple recipients of list ORACLE-L

try it:

select
  name
from
  (select c.name, count(p.id) p_count from clients c, projects p    where c.id = p.cl_id
   group by c.name) a,
  (select max(count(id)) p_max from projects     group by cl_id) b
where a.p_count = b.p_max

Regards,
Leszek

At 03:23 2002-09-30 -0800, you wrote:
>Hello all,
>
> I have a query ->
>i have 2 tables -> client and project
>
>fields in project table -> clientid/projectid
>fields in client table -> clientid/name
>
>i want to get the maximum orders one client has got. i mean a project
>having the greatest clients
>how to write it in single query ??
>
>
>like
>project 1 client 1
>project 2 client 1
>project 3 client 2
>
>in the above case, the query should return client ( 1 ).
>
>Thanks and regards,
>Santosh

--
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--
Author: Leszek Ignaszak
  INET: leszek.ignaszak_at_post.pl

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-- 
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-- 
Author: Santosh Varma
  INET: vsantosh_at_psi.soft.net

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Received on Tue Oct 01 2002 - 00:48:19 CDT