RE: SQL : where clause to include data for the previous 24 hours

or (sysdate - 18/24)

> -----Original Message-----
> From: Mercadante, Thomas F [mailto:NDATFM_at_labor.state.ny.us]
> Sent: Tuesday, April 09, 2002 9:08 AM
> To: Multiple recipients of list ORACLE-L
> Subject: RE: SQL : where clause to include data for the previous 24
> hours
>
>
> Johan,
>
> There is no need to convert sysdate to a string and back to a
> data. I'm not
> sure what you mean by "calculate the previous 24 hours when
> a query is run
> and bump the time by 6 hours".
>
> It looks like you are trying to retrieve all records that
> have a date/time
> within the last 18 hours - is this correct? if so, then your
> query would
> be:
>
> where event_date > (sysdate + 6/24) - 1
>
> The default date format really has nothing to do with how the
> dates are
> stored within the database - they are all stored the same
> way. This means
> you can do simple date math like above.
>
> Hope this is what you are looking for.
>
> Tom Mercadante
> Oracle Certified Professional
>
>
> -----Original Message-----
> Sent: Tuesday, April 09, 2002 8:13 AM
> To: Multiple recipients of list ORACLE-L
>
>
> I need a where clause to ACCURATELY (down to the second) calculate the
> previous 24 hours when a query is run and bump the time by 6 hours
> (event_date is based on GMT). The default date format has been set to
> 'SYYYY-MM-DD HH24:MI:SS','NLS_CALENDAR=GREGORIAN'.
>
> I've tried the following:
>
> " where event_date >
> (to_date(substr(sysdate,0,22),'YYYY/MM/DD HH24:MI:SS')
> + 6/24) - 1".
>
> Any ideas?
>
> --
> Please see the official ORACLE-L FAQ: http://www.orafaq.com
> --
> Author: Johan Muller
> INET: c-johan.muller_at_wcom.com
>
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> Author: Mercadante, Thomas F
> INET: NDATFM_at_labor.state.ny.us
>
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