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Re: divide with decode

From: Jared Still <jkstill_at_cybcon.com>
Date: Sun, 05 Aug 2001 14:53:38 -0700
Message-ID: <F001.00360EC7.20010805145024@fatcity.com>

Now why didn't I think of that? :)

Jared

On Saturday 04 August 2001 13:20, Larry Elkins wrote:
> Srinivas,
>
> You nearly had it. You just need to wrap each decode with a SUM (the same
> technique used to "rotate" a table except you are doing division instead of
> displaying each column):
>
> select
> sum(decode(name,'physical reads',value)) /
> sum(decode(name,'db block gets',value))
> from
> v$sysstat
> where
> name in ('db block gets','physical reads')
>
> Regards,
>
> Larry G. Elkins
> elkinsl_at_flash.net
> 214.954.1781
>
> > -----Original Message-----
> > From: root_at_fatcity.com [mailto:root_at_fatcity.com]On Behalf Of Tatireddy,
> > Shrinivas (MED, Keane)
> > Sent: Saturday, August 04, 2001 11:20 AM
> > To: Multiple recipients of list ORACLE-L
> > Subject: divide with decode
> >
> >
> > hi lists
> >
> > can anybody help me for the flwng :
> >
> > i need to do calculation dividing phy reads value/db block gets
> >
> > i am following the principle
> >
> > select decode(name,'physical reads',value)/decode(name,'db block
> > gets',value)
> > from v$sysstat
> > where name in ('db block gets','physical reads')
> >
> > just this query is returning notthing.
> >
> > i tried with to_number function also, that is not also returning
> > anything.
> >
> > is there any trick to solve this.
> >
> > srinivas
> >
> >
> >
> > --
> > Please see the official ORACLE-L FAQ: http://www.orafaq.com
> > --
> > Author: Tatireddy, Shrinivas (MED, Keane)
> > INET: Shrinivas.Tatireddy_at_med.ge.com
> >
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-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.com
-- 
Author: Jared Still
  INET: jkstill_at_cybcon.com

Fat City Network Services    -- (858) 538-5051  FAX: (858) 538-5051
San Diego, California        -- Public Internet access / Mailing Lists
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Received on Sun Aug 05 2001 - 16:53:38 CDT

Original text of this message

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