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Re: thank you, all! -- Re: Query help !!!

From: Ramana <alhassan_at_al-hassan.com>
Date: Sat, 23 Jun 2001 22:51:10 -0700
Message-ID: <F001.003358F6.20010623224520@fatcity.com>

try this..

 SELECT DISTINCT AA FROM AA A WHERE STATUS='F' AND  AA IN (SELECT AA FROM AA B WHERE A.AA=B.AA AND STATUS <> 'F'  GROUP BY B.AA HAVING COUNT(B.AA) > 1)   Ramana
>
>--- Leslie Lu <leslie_y_lu_at_yahoo.com> wrote:
>> Just to clearfy my previous question (as follow):
>>
>> if 1 has F and A and B, that what I want.
>>
>> If 1 has F all the time, that's not what I want.
>> If 1 has A, B, C, but never F, that's not what I
>> want
>> either.
>>
>> --- Leslie Lu <leslie_y_lu_at_yahoo.com> wrote:
>> > Hi,
>> >
>> > If I have this:
>> > Customer_id Status
>> > ---------- -----------
>> > 1 F
>> > 1 A
>> > 1 B
>> > 2 F
>> > 2 F
>> > 3 A
>> > 3 B
>> >
>> > How do I found out a customer who has both F and
>> not
>> > F
>> > for them. (If he only gets F, or gets other than
>> F,
>> > that's fine). In this case, I should get 1.
>> Thank
>> > you! I need this badly!
>> >
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>>
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>
>
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>--
>Please see the official ORACLE-L FAQ: http://www.orafaq.com
>--
>Author: Leslie Lu
> INET: leslie_y_lu_at_yahoo.com
>
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-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.com
-- 
Author: Ramana
  INET: alhassan_at_al-hassan.com

Fat City Network Services    -- (858) 538-5051  FAX: (858) 538-5051
San Diego, California        -- Public Internet access / Mailing Lists
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Received on Sun Jun 24 2001 - 00:51:10 CDT

Original text of this message

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